In general, the matrix itself is specified using capital letters such as A and the elements of the matrix is specified using lower case letters with subscripts such as aij where i is the row and j is the column.
A[m n] is a matrix that contains m rows and n columns.
We can view a matrix as a collection of vectors. Consider the matrix A[3 4] which is composed of 3 row vectors each consisting of 4 elements. We also note that A[3 4] is composed of 4 column vectors each consisting of 3 elements.
Please note the following:
Problems:
1) What is the notation to denote the tanspose of a matrix?
2) Give an example of a matrix A and its transpose.
3) What is the Pascal code for finding the transpose?
4) What is the C code for finding the transpose of matrix A?
5) What are the rules for adding two matrices A and B?
6) Give an example of adding two matrices A and B.
7) What is the Pascal code for adding two matrices?
8) What is the C code for adding two matrices?
9) What are the rules for multipying two matrices A and B?
10) Give and example of multiplying two matrices A and B.
11) What is the Pascal code to multiplying two matrices A and B.
12) What is the C code to multiplying two matrices A and B.
The C code will be discussed on Tuesday. Make your solutions as efficient as possible!!
1) The transpose At of an MxN matrix A is an NxM matrix.
2) A=
0 -2 1 3At=
0 1 -2 33)
for i := 1 to m do for j := 1 to n do At[j,i] := A[i,j]4) For this solution, use only pointer arithmetic!!
5) Two matrices A and B can be added provided they have the same number of rows and columns.
6)
2 1 + 5 2 = 2+5 1+2 = 7 3 -1 3 7 3 -1+7 3+3 6 67)
for i := 1 to m do for j := 1 to n do C[i,j] := A[i,j] + B[i,j]8) Again, use only pointer arithmetic.
9) Two matrices A and B can be multiplied if the number of elements in any row of A equals the number of elements in any column of B. Given, A[m n] and B[x y], the multiplication AB can be performed iff n=x. The result of the matrix multiplication C is C[m y].
Note1: Matrices are commutative over addition: A+B=B+A
Note2: Matrices are not commutative over multiplication: AB<>BA
What about associativity?
10)
2 1 + 5 2 = 2*5+1*7 2*2+1*3 = 17 7 -1 3 7 3 -1*5+3*7 -1*2+3*3 15 711)
12) Use only pointer arithmetic.
Identity Matrices have the following general form:
I = 1 0 0 0 ...... 0 1 0 0 ...... 0 0 1 0 ...... 0 0 0 1 ...... .....It is the case that AI=IA=A
We define inv(A) where A(inv(A))=(inv(A)A)=I. That is, a matrix A is said to be invertible iff there exists a matrix B such that AB=BA=I.
So how do we find inv(A)? First, let's remember how to find the determinant of a matrix.
Associated with an arbitrary element aij of A, we get an (n-1)x(n-1) matrix by deleting the ith row and the jth column. The determinant of this submatrix is called the minor of aij.
Given A=
1 0 3 4 -1 2 0 1 1
The minor of the element a11 is A11 = -3. Why?
Note1: A square matrix is said to be singular if it has a zero determinant; otherwise, it is nonsingular.
Note2: A square NxN matrix is invertible iff it is nonsingular.
Problem: Is the following matrix invertible or not?
1 -2 3 5Problem: Given the matrix A below, find inv(A).
1 2 3 41) First, is A invertible?
det(A)=-2
2) A11=4 A12=3 A21=2 A22=1
The matrix of signed minors is:
4 -3 -2 13) The transpose of this matrix (also called the adjoint matrix) is:
4 -2 -3 14) The inverse of A is (1/determinant)(adjoint matrix). So in this case:
1/(-2) 4 -2 -3 1 which is -2 1 3/2 -1/2
Does (inv(A))A=A(inv(A))=I? Problem: Given the matrix A below, find inv(A) if it exists.
1 2 0 2 1 -1 3 1 1